If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x+2x^2-8x=0
We add all the numbers together, and all the variables
2x^2-5x=0
a = 2; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·2·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*2}=\frac{0}{4} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*2}=\frac{10}{4} =2+1/2 $
| 150=70+(15+7)w | | 3k-7k-14=44 | | -4(m+3=24 | | 3x-9=-129 | | 4x-21=-81 | | (x+1)^2/5-3(x+1)^1/5+2=0 | | 13m-2/7=-4 | | k^2+12k+37=0 | | x2+5x−7x2+5x−7x=2x=2. | | |-4v-7|+8=43 | | -30=-5a-(21+8a) | | -6x^2=-x+4 | | 3k-7k=44 | | 7-(4x-3)=1-5x | | x(1/3x-1)-6(1/3x+1)=1/3x^+x-6 | | 8b+11-3b=2b=2 | | 9=5s/2-s/4 | | 13x+(-5)=10 | | 5+n/10=20 | | 2x+(2x-5)+x=65 | | w/8+3=12 | | -7y-2+y+4=44 | | -2(b-2)=2-7b | | |2x+2|=10 | | 5*x+25=50 | | 250=70+9x | | 7a-a=-4+7a | | 4-8c=8 | | (8x+7)^2=36 | | 5+2(6+6x)=101 | | 3(x-4)=7x+4 | | 11x+(-12)=-9 |